z(z^2+3z-9)=27

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Solution for z(z^2+3z-9)=27 equation: 


Simplifying
z(z2 + 3z + -9) = 27

Reorder the terms:
z(-9 + 3z + z2) = 27
(-9 * z + 3z * z + z2 * z) = 27
(-9z + 3z2 + z3) = 27

Solving
-9z + 3z2 + z3 = 27

Solving for variable 'z'.

Reorder the terms:
-27 + -9z + 3z2 + z3 = 27 + -27

Combine like terms: 27 + -27 = 0
-27 + -9z + 3z2 + z3 = 0

The solution to this equation could not be determined.

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